16c^2-22c+7=0

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Solution for 16c^2-22c+7=0 equation:


Simplifying
16c2 + -22c + 7 = 0

Reorder the terms:
7 + -22c + 16c2 = 0

Solving
7 + -22c + 16c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -2c)(7 + -8c) = 0

Subproblem 1

Set the factor '(1 + -2c)' equal to zero and attempt to solve: Simplifying 1 + -2c = 0 Solving 1 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2c = 0 + -1 -2c = 0 + -1 Combine like terms: 0 + -1 = -1 -2c = -1 Divide each side by '-2'. c = 0.5 Simplifying c = 0.5

Subproblem 2

Set the factor '(7 + -8c)' equal to zero and attempt to solve: Simplifying 7 + -8c = 0 Solving 7 + -8c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -8c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -8c = 0 + -7 -8c = 0 + -7 Combine like terms: 0 + -7 = -7 -8c = -7 Divide each side by '-8'. c = 0.875 Simplifying c = 0.875

Solution

c = {0.5, 0.875}

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